AP EAMCET202315 May 2023Evening ShiftMathematicsDifferentiationActual
If f(x+a y)+g(x-a y)=0 , then a d y d x =
Options
- Af^ (x-a y)+g^ (x+a y) g^ (x+a y)-f^ (x-a y)
- Bf^ (x+a y)+g^ (x-a y) g^ (x-a y)-f^ (x+a y)
- Cf^ (x+a y) g^ (x-a y) f^ (x+a y)+g^ (x-a y)
- Df^ (x+a y)+g^ (x-a y) f^ (x+a y) g^ (x-a y)
Correct answer
B. f^ (x+a y)+g^ (x-a y) g^ (x-a y)-f^ (x+a y)
Step-by-step solution
Given, f(x+a y)+g(x-a y)=0 differentiating w.r. to x aligned & f^ (x+a y) (1+a y^ )+g^ (x-a y)(1-a y)=0 & a y^ (f^ (x+a y)-g^ (x-a y)+f(x+a y)+g^ (x-a y)=0 . & a y^ = f^ (x+a y)+g^ (x-a y) g^ (x-a y)-f^ (x+a y) aligned