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NEET2022PhysicsMotion in Two DimensionsActual

A ball is projected with a velocity, 10   m   s - 1 , at an angle of 60 ° with the vertical direction. Its speed at the highest point of its trajectory will be

Options

  1. A5 3   m   s - 1
  2. B5   m   s - 1
  3. C10   m   s - 1
  4. DZero

Correct answer

A. 5 3   m   s - 1

Step-by-step solution

The speed of a projectile at highest point is equal to the component of velocity of projection along the horizontal direction. The angle given with the vertical is 60 ° therefore, the angle with the horizontal will be 30 ° . Therefore, V = u cos θ ⇒ V = 10 cos 30 ° = 10 × 3 2 ⇒ V = 5 3   m   s - 1

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