If displacement s=5 (2 t) , then the velocity at the end of 3 ~s is

Step-by-step solution

s=5 (2 t) differentiate w.r.t. ' t ' aligned & d s d t =5 d d t (2 t) & d s d t =5 (2 t) 2=10 2 t aligned Velocity when t= 3 = . d s d t |_ t= / 3 =10 2 ( 3 ) =10 - 1 2 =-5 Hence, option (4) is correct.