The potential energy of a long spring when stretched by 2   cm is U . If the spring is stretched by 8   cm , potential energy stored in it will be:

Step-by-step solution

Potential energy stored in spring is given by, U = 1 2 K x 2 . First case: U = 1 2 K 2 × 10 - 2 2       . . . E q 1 Second case: U ' = 1 2 K 8 × 10 - 2 2         . . . E q 2 From both equations, we get U U ' = 1 16 ⇒ U ' = 16 U