A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of the earth and the speed of the particle at that instant are respectively___

Step-by-step solution

∵ At Every p t . K E + P E = constant so, ( K E ) A + ( P E ) A = ( K E ) B + ( P E ) B 0 + m g S = 3 ( P E ) B + ( P E ) B m g S = 4 m g h h = S 4 Now, K E at p   t   .   B - ∵ At p   t   .   B - K E = 3 P E 1 2 m v 2 = 3 m g s 4 v = 3 2 g S