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NEET 2018
Exam
NEET
Year
2018
Subject
Physics
Chapter
Work, Power and Energy

NEET 2018 · Physics · Work, Power and Energy

A body initially at rest and sliding along a frictionless track...

A body initially at rest and sliding along a frictionless track from a height hh (as shown in the figure) just completes a vertical circle of diameter AB=DAB = D. The height hh is equal to,
A body initially at rest and sliding along a frictionless track from a height h (as shown in the figure) just completes

Options

  1. A75D\dfrac{7}{5}D
  2. BDD
  3. C32D\dfrac{3}{2}D
  4. D54D\dfrac{5}{4}D

Correct answer

D. 54D\dfrac{5}{4}D

Step-by-step solution

To just complete a vertical circle, speed at A should be

vA=5gR{v}_{A} = \sqrt{5gR}

Using energy conservation

mgh=12mvA2mgh = \dfrac{1}{2}m{v}_{A}^{2}

h=12vA2g=125ggD2h = \dfrac{1}{2}\dfrac{{v}_{A}^{2}}{g} = \dfrac{1}{2}\dfrac{5g}{g}\dfrac{D}{2} \left(R = \dfrac{D}{2}\right)<br/><br/><br /><br />h = \dfrac{5D}{4}
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