NEET2019PhysicsWork, Power and EnergyActual
A force F = 20 + 10 y acts on a particle in y -direction where F is in Newton and y is in meter. Work done by this force to move the particle from y = 0 to y = 1   m is
Options
- A30 J
- B5 J
- C25 J
- D20 J
Correct answer
C. 25 J
Step-by-step solution
Work done is calculated by taking the dot product between the force and the displacement. W = ∫ F · d y = ∫ 0 1 20  d y + ∫ 0 1 10   y   d y = 20   y 0 1 + 5 y 2 0 1 = 20 + 5 = 25   J