Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEET2019PhysicsWork, Power and EnergyActual

A force F = 20 + 10 y acts on a particle in y -direction where F is in Newton and y is in meter. Work done by this force to move the particle from y = 0 to y = 1   m is

Options

  1. A30 J
  2. B5 J
  3. C25 J
  4. D20 J

Correct answer

C. 25 J

Step-by-step solution

Work done is calculated by taking the dot product between the force and the displacement. W = ∫ F · d y = ∫ 0 1 20  d y + ∫ 0 1 10   y   d y = 20   y 0 1 + 5 y 2 0 1 = 20 + 5 = 25   J

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All NEET PYQs