NEET2025PhysicsWork, Power and EnergyActual
The kinetic energies of two similar cars A and B are 100 J and 225 J respectively. On applying breaks, car A stops after 1000 m and car B stops after 1500 m . If F _ A and F _ B are the forces applied by the breaks on cars A and B , respectively, then the ratio F _ A / F _ B is :
Options
- A3 2
- B2 3
- C1 3
- D1 2
Correct answer
B. 2 3
Step-by-step solution
aligned & W.D. = KE aligned F . S = KE aligned & ( K E)_A ( K E)_B = - F _A S_A - F _ B ~S _ B & -100 -225 = - F _ A (1000) - F _ B (1500) & F _ A ~F _ B = 2 3 aligned