NEET2012PhysicsWork, Power and EnergyActual
The potential energy of a particle in a force field is U= A r^2 - B r , where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is
Options
- AB / 2 A
- B2 A / B
- CA / B
- DB / A
Correct answer
B. 2 A / B
Step-by-step solution
Given, the potential energy of a particle in a force field U= A r^2 - B r^1 For stable equilibrium, F=- d U d r =00=- 2 A r^3 + B r^2 or 2 A r =B The distance of particle from the centre of the field r= 2 A B