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NEET2012PhysicsWork, Power and EnergyActual

The potential energy of a particle in a force field is U= A r^2 - B r , where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is

Options

  1. AB / 2 A
  2. B2 A / B
  3. CA / B
  4. DB / A

Correct answer

B. 2 A / B

Step-by-step solution

Given, the potential energy of a particle in a force field U= A r^2 - B r^1 For stable equilibrium, F=- d U d r =00=- 2 A r^3 + B r^2 or 2 A r =B The distance of particle from the centre of the field r= 2 A B

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