The potential energy of a particle in a force field is U=(A)/(r^2)-(B)/(r) , where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of

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Correct answer: B. 2 A / B

Given, the potential energy of a particle in a force field U=(A)/(r^2)-(B)/(r^1) For stable equilibrium, F=-(d U)/(d r)=0 0=-(2 A)/(r^3)+(B)/(r^2) or (2 A)/(r)=B The distance of particle from the centre of the field r=(2 A)/(B)

The potential energy of a particle in a force field is...

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