NEET2009PhysicsWork, Power and EnergyActual
A block of mass M is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value k . The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be :
Options
- AMg / 2 k
- BMg / k
- C2 Mg / k
- D4 Mg / k
Correct answer
C. 2 Mg / k
Step-by-step solution
Loss in grav. PE = gain in spring PE At maximum elongation aligned Mgx & = 1 2 kx ^2 x & = 2 Mg k aligned