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NEET2009PhysicsWork, Power and EnergyActual

A block of mass M is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value k . The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be :

Options

  1. AMg / 2 k
  2. BMg / k
  3. C2 Mg / k
  4. D4 Mg / k

Correct answer

C. 2 Mg / k

Step-by-step solution

Loss in grav. PE = gain in spring PE At maximum elongation aligned Mgx & = 1 2 kx ^2 x & = 2 Mg k aligned

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