NEET2006PhysicsWork, Power and EnergyActual
300 ~J of work is done in sliding a 2 ~kg block up an inclined plane of height 10 m . Taking g=10 ~m / s ^2 , work done against friction is:
Options
- A1000 ~J
- B200 ~J
- C100 ~J
- Dzero
Correct answer
C. 100 ~J
Step-by-step solution
Potential energy aligned & =2 10 10 & =200 ~J aligned and work done =300 ~J Work done against friction =300-200=100 ~J .