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NEET 2006

Exam: NEET
Year: 2006
Subject: Physics
Chapter: Work, Power and Energy

NEET 2006 · Physics · Work, Power and Energy

300 ~J of work is done in sliding a 2 ~kg block up an inclined...

300 \mathrm{~J}

of work is done in sliding a

2 \mathrm{~kg}

block up an inclined plane of height 10

\mathrm{m}

. Taking

g=10 \mathrm{~m} / \mathrm{s}^2

, work done against friction is:

Options

A $1000 \mathrm{~J}$
B $200 \mathrm{~J}$
C $100 \mathrm{~J}$
Dzero

Correct answer

C. $100 \mathrm{~J}$

Step-by-step solution

Potential energy

\begin{aligned}& =2 \times10 \times10 \\ & =200 \mathrm{~J} \end{aligned}

and work done

=300 \mathrm{~J}\therefore

Work done against friction =300-200=100

\mathrm{~J} .

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