NEET2005PhysicsWork, Power and EnergyActual
A force F acting on an object varies with distance x as shown here. The force is in N and x in m . The work done by the force in moving the object x=0 to x=6 ~m is:
Options
- A18.0 ~J
- B13.5 ~J
- C9.0 ~J
- D4.5 ~J
Correct answer
B. 13.5 ~J
Step-by-step solution
Work done = Area under =f-x curve. aligned & = area of trapezium = 1 2 (6+3) 3 & = 27 2 =13.5 ~J aligned