The potential energy of a long spring when stretched by 2 ~cm is U . If the spring is stretched by 8 ~cm the potential energy stored in it is:

Step-by-step solution

Potential energy of a spring aligned & aligned &= 1 2 force constant & ( extension )^2 & Potential energy ( extension )^2 aligned & Hence U₁ V₂ = ( x₁ x₂ )^2 & V₁ V₂ = ( 2 8 )^2 & U₁ U₂ - 1 16 ( U₁=V ) aligned