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NEET 2006
Exam
NEET
Year
2006
Subject
Physics
Chapter
Work, Power and Energy

NEET 2006 · Physics · Work, Power and Energy

The potential energy of a long spring when stretched by 2 ~cm is U...

The potential energy of a long spring when stretched by 2 cm2 \mathrm{~cm} is UU. If the spring is stretched by 8 cm8 \mathrm{~cm} the potential energy stored in it is:

Options

  1. AU/4U / 4
  2. B4U4 U
  3. C8U8 U
  4. D16U16 U

Correct answer

D. 16U16 U

Step-by-step solution

Potential energy of a spring \begin{aligned} & \begin{aligned} &= \frac{1}{2} \times \text{ force constant } \\ & \times(\text{ extension })^2 \\ & \Rightarrow \text{ Potential energy } \propto(\text{ extension })^2 \end{aligned} \\ & \text{Hence } \frac{U_1}{V_2}=\left(\frac{x_1}{x_2}\right)^2 \\ & \Rightarrow \frac{V_1}{V_2}=\left(\frac{2}{8}\right)^2 \\ & \Rightarrow \frac{U_1}{U_2}- \frac{1}{16}\left(\because U_1=V\right) \end{aligned}$
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