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AP EAMCET202017 Sep 2020Evening ShiftMathematicsDifferentiationActual

If ( (x+y)-2 x y=0 ), then (y^ (0)= )

Options

  1. A(2 y^2+1 )
  2. B(2 y^2-1 )
  3. C0
  4. D(2 y^2 )

Correct answer

B. (2 y^2-1 )

Step-by-step solution

( (x+y)-2 x y=0 ) Differentiating with respect to ' (x ) ' we get, ( aligned 1 x+y (1+ d y d x )-2 (x d y d x +y ) & =0 1 x+y + ( 1 x+y -2 x ) d y d x -2 y & =0 aligned ) ( aligned & d y d x = 2 y- 1 x+y 1 x+y -2 x & . d y d x |_ x=0 = 2 y- 1 y 1 y =2 y^2-1 aligned )

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