If y = sin 2 cot - 1 1 + x 1 - x , then d y d x =

Step-by-step solution

The equation is given as, y = sin 2 cot - 1 1 + x 1 - x Substitute x = cos 2 θ   … I y = sin 2 cot - 1 1 + cos 2 θ 1 - cos 2 θ y = sin 2 cot - 1 2 cos 2 θ 2 sin 2 θ y = sin 2 cot - 1 ( cot θ ) y = sin 2 θ   … II Differentiate the above equation with respect to θ , d y d θ = 2 sin θ cos θ d y d θ = sin 2 θ Differentiate the above equation (I) with respect to θ , d x d θ = - 2 sin 2 θ From equation III   and &#1