Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201822 Apr 2018Evening ShiftMathematicsDifferentiationActual

For -1 < x < 1 , if f(x)= ^2 ( ⁻¹ 1-x 1+x ) , then f^ (x)=

Options

  1. A1 2
  2. B1
  3. C-1
  4. D-1 2

Correct answer

A. 1 2

Step-by-step solution

Given function f(x)= ^2 ( ^1 1-x 1+x ) , for -1 < x < 1 . Let x= 2 Then, 1-x 1+x = 1- 2 1+ 2 = ^2 So, f(x)= ^2 = 1+ 2 2 = 1+x 2 So, f^ (x)= 1 2 .

Practice Differentiation on Quantrex Academy →

More from Differentiation

The domain of the derivative of the function f(x)= x 1+|x| is 2025If x= 2^ cosec ⁻¹ t and y= 2^ ⁻¹ t ,|t| 1 then d y d x = 2025If (a+ 2 b x)(a- 2 b y)=a^2-b^2 where a>b>0 , then at ( 4 , 4 ) , dy dx = 2025If x y - y x =0 , then d y d x = 2025If y = ( _ x x )^ x , then dy dx = 2025If f(x)=x^ Sec ⁻¹ x , then f^ (2)= 2025If y= x^4 3 x-5 (x^2-3 )(2 x-3) , then ( d y d x )_ x=2 = 2025If x^2+y^2+ y=4 , then the value of d^2 y d x^2 at x=-2 is 2025 Full Differentiation list All AP EAMCET PYQs