At a particular locus, frequency of A allele is 0.6 and that of a is 0.4 . What would be the frequency of heterozygotes in a random mating population at equilibrium?

Step-by-step solution

In a stable population, for a gene with two alleles, 'A' (dominant) and 'a' (recessive), the frequency of ' A ^ = p the frequency of ' a ' =q , According Hardy-Weinberg equation: p ^2+2 p q+q^2=1 where p ^2= Frequency of A (homozygous dominant) individuals q ^2= Frequency of aa (homozygous recessive) individuals 2 pq = Frequency of Aa (heterozygous) individuals. aligned & 2 pq ( frequency of heterozygote )= & 2 0.6 0.4=0.48 aligned