If y= ⁻¹ ( a^2-x^2 a^2+x^2 )+ ⁻¹ ( 2 a x a^2+x^2 ) , then d y d x is equal to

Step-by-step solution

y= ⁻¹ ( a^2-x^2 a^2+x^2 )+ ⁻¹ ( 2 a x a^2+x^2 ) Put x=a = ⁻¹ ( x a )y= ⁻¹ ( a^2-a^2 ^2 a^2+a^2 ^2 )+ ⁻¹ ( 2 a^2 a^2+a^2 ^2 ) y= ⁻¹ ( 1- ^2 1+ ^2 )+ ⁻¹ ( 2 1+ ^2 ) y= ⁻¹( 2 )+ ⁻¹( 2 ) [ array l 2 = 1- ^2 1+ ^2 ^2 = 2 1+ ^2 array ] y=2 +2 y=4 y=4 ⁻¹ ( x a ) d y d x =4 1 1+ x^2 a^2 1 a =4 a^2 a^2+x^2 1 a d y d x = 4 a a^2+x^2