In a population of 1000 moths, 450 moths were brown-colored with homozygous genotype and 350 albino moths that were homozygous for the recessive allele. Assuming random mating within the population, the frequency of heterozygotes in the next generation would be:

Step-by-step solution

Total number of moths = 1000 Number of homozygous dominant moths (BB) = 450 Number of homozygous recessive moths (bb) = 350 Number of heterozygous moths (Bb) = 1000 - (450 + 350) = 200 Total number of alleles in the population = 1000 2 = 2000 Number of dominant alleles (B) = (450 2) + 200 = 1100 Frequency of dominant allele p = 1100 2000 = 0.55 Number of recessive alleles (b) = (350 2) + 200 = 900 Frequency of recessive allele q = 900 2000 = 0.45 Assuming random mating, the population in the next generation will fo