NEST2023ChemistryBiomolecules
In an aqueous solution, glucose exists in cyclic and open-chain forms, in equilibrium, as shown below. Glucose solution does not give positive Schiff test. The correct statement is:
Options
- A- D (+) -glucose and - D (+) -glucose are enantiomers.
- B- D (+) -glucose and - D (+) -glucose are anomers.
- CIn solution, the open-chain form predominates over the cyclic forms.
- DGlucose reacts with sodium bisulphite to form an addition product.
Correct answer
B. - D (+) -glucose and - D (+) -glucose are anomers.
Step-by-step solution
No solution available.