NEST2020ChemistryChemical Bonding and Molecular Structure
Three types of potential energy due to attractive interaction between two species X and Y are represented by the curves I, II, and III in the figure below. Consider the dominating interaction between non-rotating species ( X Y ) for X = Na ⁺, ( CH ₃ )₂ CO , C ₆ H ₆, CH ₄ and Y = ( CH ₃ )₂ CO , Cl ⁻, C ₂ H ₆, CHCl ₃ . The correct assignment of the X Y interactions to the types I, II, and III is:
Options
- ANa ⁺ Cl ⁻= III ; ( C ₆ H ₆ ) ( CH ₃ )₂ CO = I ; ( CH ₄ ) ( C ₂ H ₆ )= II ; ( CH ₃ )₂ CO CHCl ₃= III .
- BNa ⁺ Cl ⁻= III ; ( C ₆ H ₆ ) ( CH ₃ )₂ CO = I ; ( CH ₄ ) ( C ₂ H ₆ )= I ; ( CH ₃ )₂ CO CHCl ₃= II .
- CNa ⁺ Cl ⁻= II ; ( C ₆ H ₆ ) ( CH ₃ )₂ CO = II ; ( CH ₄ ) ( C ₂ H ₆ )= III ; ( CH ₃ )₂ CO CHCl ₃= I .
- DNa ⁺ Cl ⁻= I ; ( C ₆ H ₆ ) ( CH ₃ )₂ CO = III ; ( CH ₄ ) ( C ₂ H ₆ )= II ; ( CH ₃ )₂ CO ₂ CHCl ₃= II .
Correct answer
B. Na ⁺ Cl ⁻= III ; ( C ₆ H ₆ ) ( CH ₃ )₂ CO = I ; ( CH ₄ ) ( C ₂ H ₆ )= I ; ( CH ₃ )₂ CO CHCl ₃= II .
Step-by-step solution
No solution available.