Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEST2024ChemistryIonic Equilibrium

Consider two sparingly soluble salts P Q and R S ₂ . At temperature T ₀ , the solubility products of these two salts are found to be equal. At a higher temperature T ₁ ( ~T ₁ T ₀ ) , the solubility of PQ becomes triple of its solubility at T ₀ . Also, at another temperature T₂ (T₂ T₀ ) , the solubility of R S _ 2 becomes double of its solubility at T₀ . The ratio of solubility products of P Q at T₁ and R S _ 2 at T ₂

Options

  1. A1
  2. B9 / 8
  3. C9 / 32
  4. D3 / 2

Correct answer

B. 9 / 8

Step-by-step solution

No solution available.

Practice Ionic Equilibrium on Quantrex Academy →

More from Ionic Equilibrium

At 30°C the solubility of PbI₂ salt in 0.2 M KI solution will be X, if the solubility product of PbI₂ at 30°C is 2.4 10⁻⁸ . Identify the value of X. 2026A 0.15 mole of pyridinium chloride has been added to 500 cm ^3 of 0.2 M pyridine solution (a base). Assuming there is no change in volume upon mixing(Given: pK_b of pyridine = 8.82 2026At T ( K ) K _ sp of two ionic salts MX ₂ and MX is 5 10⁻¹³ and 1.6 10⁻¹¹ respectively. The ratio of molar solubility of MX ₂ and MX is 2025The conjugate base of phosphorus acid is x . The conjugate base of oleum is y . What are x and y , respectively? 2025The molar solubility of PbI ₂ in 0.2 M Pb ( NO ₃ )₂ solution in terms of K _ sp (solubility product) is 2025When 30 mL of 0.2 M NH ₄ OH is added to 30 mL of 2 M NH ₄ Cl solution. If the pH of the buffer formed is 8.2, what is the pK _ b of NH ₄ OH ? 2025The percentage of ionization of 1 L of x M acetic acid is 4.242 and is called solution "A". The percentage of ionization of 1 L of y M acetic acid is 3 and is called solution "B". 2025At 25^ C , the percentage of ionization of ' x ' M acetic acid is 4.242. What is the value of x ? ( ~K _ a =1.8 10⁻⁵ ) 2025 Full Ionic Equilibrium list All NEST PYQs