NEST2018Chemistryp Block Elements (Group 13 & 14)
Oxidation of NaBH ₄ with iodine results in evolution of a colorless gas, X , along with formation of NaI and hydrogen gas. Three moles of X react with six moles of NH ₃ to give an intermediate which upon heating results in Y accompanied by evolution of hydrogen gas. Compounds X and Y , respectively, are
Options
- ABH ₃, H ₃ ~B NH ₃
- BB ₂ H ₆, H ₃ ~B NH ₃
- CB ₂ H ₆, ~B ₃ ~N ₃ H ₆
- DBH ₃, [ BH ₂ ( NH ₃ )₂ ]⁺ [ BH ₄ ]⁻
Correct answer
C. B ₂ H ₆, ~B ₃ ~N ₃ H ₆
Step-by-step solution
No solution available.