NEST2012ChemistryStates of Matter
The probability distribution for the speed (v) of molecules for an ideal gas at temperature T , is given by f(v)=4 v^2 ( m 2 k_B T )^ 3 / 2 (- m v^2 2 k_B T ) where m is the mass of a molecule and k_ B is the Boltzmann constant. Among the following, the correct statement is
Options
- AThe most probable velocity is proportional to T^ 3 / 2 .
- BFor two different gases A and B , the average velocity of the molecules of A is same as that of B , at a given
- CFor two different gases A and B, the average kinetic energy of the molecules of A is same as that of B , at a
- DThe most probable velocity is higher than the average velocity.
Correct answer
C. For two different gases A and B, the average kinetic energy of the molecules of A is same as that of B , at a
Step-by-step solution
No solution available.