NEST2019ChemistryStructure of Atom
The ground state energy of hydrogen atom in the n^ th stationary state is given by the expression E_n=- (2 ^2 ) m e^4 / ( n ^2 h^2 ) , where m (=m_e m_p / ( m _e+ m _p ) ) is the reduced mass, e is the electronic charge, and m _c and m _p are the mass of electron and proton, respectively. The ground state energy of hydrogen atom as calculated by this expression is -13.6 eV . If the first ionization potential of deute
Options
- AI _D=27.2 eV .
- BI _D 13.6 eV
- CI _D 13.6 eV
- DI _D=13.6 eV .
Correct answer
C. I _D 13.6 eV
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