NEST2019MathematicsApplication of Derivatives
Let f:(0, ) R be a function defined as f(x)= x e^ -x 1+x . Then
Options
- Af is a strictly decreasing function on (0, )
- Bf is a surjective function
- Cf is a strictly increasing function on (0, )
- Dthere exists a unique x₀ (0, ) such that f (x₀ ) f^ (x₀ ) 0
Correct answer
D. there exists a unique x₀ (0, ) such that f (x₀ ) f^ (x₀ ) 0
Step-by-step solution
No solution available.