Let a function f:[0, ) R be defined as follows. f(x)= cases |x-a|-1, & 0 x 2 b(x-2)^2, & x 2 cases where a and b are real numbers with a (0,2) and b 0 . Then

Options

1. Athere is exactly one value of a which makes f a continuous function.
2. Bthe continuity of f depends on the values of both a and b .
3. Cf is continuous if and only if a+b=1 .
4. Df is not differentiable at exactly one point in its domain.