NEST2012MathematicsProbability
A fair coin is repeatedly tossed. Let X be the event that we get at least 2 heads in 4 tosses and Y be the event that we get at least 3 heads in 6 tosses. Then
Options
- AX is a more likely event than Y .
- BY is a more likely event than X .
- Cboth events are equally likely.
- Dgiven data is insufficient to draw any such conclusion.
Correct answer
A. X is a more likely event than Y .
Step-by-step solution
No solution available.