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NEST2020MathematicsSequences and Series

For n N , let f(n)= cases 3 n+1 & if n is odd n 2 & if n is even cases Define f^ (1) (n)=f(n) and f^ (i) (n)=f (f^ (i-1) (n) ) for i 1 . Suppose l is an even number greater than or equal to 2020. Then the least value of i for which f^ (i) ( 2^ (2^ -1 ) 3 )=1 is

Options

  1. A2 -1
  2. B2 +2
  3. C2 +1
  4. D2

Correct answer

C. 2 +1

Step-by-step solution

No solution available.

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