NEST2024PhysicsGravitation
Recent observations show that apart from the gravitational attraction, there is another force due to "dark energy" at large scales in the universe. This can be modelled in Newtonian physics by modifying the gravitational potential energy of a system of mass M and m separated by a distance r to include a universal repulsive force V=- G M m r - m r^2 6 . Here is a positive constant called the cosmological constant. A p
Options
- AAcceleration is equal to times the displacement from the equilibrium point and away from the equilibrium point
- BParticle oscillates about the equilibrium point with angular frequency = / 3 .
- CEquilibrium point is at r=(6 G M / )^ 1 / 3 .
- DAcceleration is equal to / 3 times the displacement from the equilibrium point and towards the equilibrium poi
Correct answer
A. Acceleration is equal to times the displacement from the equilibrium point and away from the equilibrium point
Step-by-step solution
No solution available.