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NEST2014PhysicsThermodynamics

The three processes in a thermodynamic cycle shown in the figure are: Process 1 2 is isothermal; Process 2 3 is isochoric (volume remains constant); Process 3 1 is adiabatic. The total work done by the ideal gas in this cycle is 10 J . The internal energy decreases by 20 J in the isochoric process. The work done by the gas in the adiabatic process is -20 J . Then

Options

  1. Athe net change in the internal energy in the cycle is 0 J .
  2. Bthe work done by the gas in the isochoric process is 0 J .
  3. CThe change in the internal energy in the adiabatic process is 30 J .
  4. Dthe heat added to the system in the isothermal process is 30 J .

Correct answer

D. the heat added to the system in the isothermal process is 30 J .

Step-by-step solution

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