If a 0 and the line 2 b x+3 c y+4 d=0 , passes through the points of intersection of the parabolas y^2=4 a x and x^2=4 a y , then

Step-by-step solution

y^2=4 a x, x^2=4 a y clearly they are symmetric w.r.t y=x . y=x also pass through their point of intersections. i.e., solving y^2=4 a x and y=x x^2=4 a x x=0,4 a When x=0, y=0 ; x=4 a y=4 a (0,0) &(4 a, 4 a) are the points of intersection. 2 b x+3 c y+4 d=0 passes through (0,0) &(4 a, 4 a) (given) d=0 and (2 b+3 c)=0 d^2+(2 b+3 c)^2=0