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AP EAMCET201922 Apr 2019Morning ShiftMathematicsFunctionsActual

If (f: R R ) is defined by (f(x)= cases |[x-5]|, & for x < 5 [|x-5|], & for x 5 cases ) Then, ((f f) (- 7 2 )= ) (here, ([x] ) is the greatest integer not exceeding (x ))

Options

  1. A((f f) (- 11 2 ) )
  2. B((f f) (- 9 2 ) )
  3. C((f f)(3) )
  4. D((f f) ( 9 2 ) )

Correct answer

D. ((f f) ( 9 2 ) )

Step-by-step solution

(f f (- 7 2 )=f [ [- 7 2 -5 ]=f(9)=|[19-51]|=4 . ) By checking option (A) ( f ( [- 11 2 -5 ] )=6 ) (B) ( f f (- 9 2 )=5 ) (C) ( f o f(3)=3 ) (D) ( f f ( 9 2 )=f( l )=4 ) Hence, option (d) is correct.

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