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AP EAMCET2016MathematicsFunctions

If f(x)=|x-1|+|x-2|+|x-3|, 2 < x < 3 , then f is

Options

  1. Aan onto function but not one-one
  2. Bone-one function but not onto
  3. Ca bijection
  4. Dneither one-one nor onto

Correct answer

C. a bijection

Step-by-step solution

We have, aligned & f(x)=|x-1|+|x-2|+|x-3| & f(x)= array cc 6-3 x, & x 3 array . aligned For 2 < x < 3 , then f(x)=x So, f(x) is one-one and onto function. It implies that f(x) is a bijection.

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