Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET2013MathematicsFunctions

Let f be a non-zero real valued continuous function satisfying f(x+y)=f(x) f(y) for all x, y R . If f(2)=9 , then f(6) is equal to

Options

  1. A3^2
  2. B3^6
  3. C3^4
  4. D3^3

Correct answer

B. 3^6

Step-by-step solution

f(x+y)=f(x) f(y), x, y R Put x=y=1 , we get aligned & f(2)=f(1) f(1)=9 [ f(2)=9] & f(1)^2=9 f(1)=3 & aligned Now, put x=2 and y=1 in Eq. (i), we get f(3)=f(2) f(1)=3^2 3=3^3 Now, put x=3 and y=1 in Eq. (i), we get f(4)=f(3) f(1)=3^3 3=3^4 Again, put x=4 and y=2 in Eq. (i), we get f(6)=f(4) f(2)=3^4 3^2=3^6 Alternative Method We have, aligned f(x+y) & =f(x) f(y), x, y R f(2) & =9 aligned and Now, aligned f(1+1) & =f(1) f(1) f(2) & = f(1) ^2 f(1) & = f(2) aligned Now, f(1) = f(2) f(6)=f(1+1+1+1+1+1) aligned & =f(1) f

Practice Functions on Quantrex Academy →

More from Functions

If f : R A , defined by f ( x )= x + 3 x -1 , is an onto function then A = 2025Let g(x)=1+x-[x] and f(x)= cases -1, & x 0 cases ([x] ) denotes the greatest integer less than or equal to (x ). Then for all x , f ( g ( x ))= 2025The domain of the real valued function f(x)= 3 4-x^2 + ₁₀ (x^3-x ) is 2025A real valued function f: A B defined by f(x)= 4-x^2 4+x^2 x A is a bijection. If -4 A then A B= 2025Let [ x ] represent the greatest integer less than or equal to x , x = x -[ x ] , 2 =1.414 and 3 =1.732 . If f(x)= x+ [ x 1+x^2 ] is a real valued function, then f ( 2 )+ f (- 3 )= 2025If the range of the function f(x)=-3 x-3 is 3,-6,-9,-18 , then which one of the following is not in the domain of f ? 2025The domain of the function f(x)= _e ( 1 x^2-4 x+4 ) + ⁻¹ (x^2-2 ) is 2025Consider the following statements Statement-I : A function f : A B is said to be one-one if and only if f(x) f(y) x y Statement-II : A relation f: A B is said to be a function if x 2025 Full Functions list All AP EAMCET PYQs