Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET202422 May 2024Morning ShiftMathematicsHyperbolaActual

If the eccentricity of the hyperbola x^2 a^2 - y^2 b^2 =1 is , then area of the triangle formed by the asymptotes of the hyperbola with any of its tangent is

Options

  1. Aa^2 b^2 ^2
  2. Bb^2 | |
  3. Ca^2 ^2
  4. D(a^2+b^2 ) ^2

Correct answer

B. b^2 | |

Step-by-step solution

x^2 a^2 - y^2 b^2 =1 We know, area of triangle formed by the asymptotes of the hyperbola with any of its tangent is a b . Now, e^2= ^2 aligned & 1+ b^2 a^2 =1+ ^2 b^2 a^2 = ^2 & b^2 ^2 =a^2 b^4 ^2 =a^2 b^2 & b^2 | | =a b aligned

Practice Hyperbola on Quantrex Academy →

More from Hyperbola

The difference between the distance of any point on the hyperbola from the two foci is 16 and the eccentricity is 2 . Then the equation of the hyperbola is 2026In the figure Statement-I: When > 0 , the section is hyperbola Statement-II: When > 90^ , the section is ellipse Which of the following is correct? 2026If the line y = 2x + is a tangent to the hyperbola 36x^2 - 25y^2 = 3600 , then = 2026If the line 4x + 3y = 7 touches the hyperbola x^2 - y^2 = 7 , then the sum of the co-ordinates of the point of contact is... 2026If the eccentricity of the hyperbola x^2 a^2 - y^2 b^2 =1 passing through the point (4,6) is 2, then the equation of the tangent to this hyperbola at (4,6) is 2025A hyperbola passes through the point P ( 2 , 3 ) and has foci at ( 2,0) . Then the point that lies on the tangent drawn to this hyperbola at P is 2025If is the angle subtended by a latus rectum at the centre of the hyperbola having eccentricity 2 7 - 3 , then = 2025The tangent drawn at an extremity (in the first quadrant) of latus rectum of the hyperbola x^2 4 - y^2 5 =1 meets the x -axis and y -axis at A and B respectively. If O is the origi 2025 Full Hyperbola list All AP EAMCET PYQs