NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice
If f ( x ) = x 3 + 4 x 2 + λx + 1 is a monotonically decreasing function of x in the largest possible interval ( - 2 ,   - 2 3 ) , then
Options
- Aλ = 4
- Bλ = 2
- Cλ = -1
- Dλ has no real value
Correct answer
A. λ = 4
Step-by-step solution
Here, f ' ( x ) ≤ 0 ⇒ 3 x 2 + 8 x + λ ≤ 0 ,   ∀ x ∈ - 2 , - 2 3 Then, situations for f ' ( x ) is as follow : Given that f ( x ) decreases in the largest possible interval - 2 , - 2 3 then f ' ( x )   =   0 must have roots - 2 and - 2 3 ⇒ Product of roots is ( - 2 ) - 2 3 = λ 3 ⇒ λ = 4