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NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice

The minimum value of the expression 3 x + 2 y ( ∀ x , y > 0 ), where x y 2 = 10, occurs when the value of y is equal to

Options

  1. A10
  2. B10 3
  3. C30 3
  4. D1 30

Correct answer

C. 30 3

Step-by-step solution

3 x + 2 y = 3 10 y 2 + 2 y = f y = 30 y 2 + y + y Minimum value occurs when y = 30 1 3 u s i n g A M ≥ G M

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