NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice
The maximum slope of the curve y = - x 3 + 3 x 2 - 4 x + 9 is
Options
- A1
- B– 1
- C2
- D3
Correct answer
B. – 1
Step-by-step solution
d y d x = - 3 x 2 + 6 x - 4 = Z l e t For maximum value of Z, d Z d x = 0 - 6 x + 6 = 0 x = 1 d 2 Z d x 2 = - 6 < 0 so, maxima occurs at x = 1 Z m a x = - 3 + 6 - 4 = - 1