NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice
A cone having fixed volume has semi-vertical angle of π 4 . At an instant when its height is decreasing at the rate of 2 m / s, its radius increases at a rate equal to
Options
- A2 m / s
- B4 m / s
- C1 m / s
- D8 m / s
Correct answer
C. 1 m / s
Step-by-step solution
As, V = 1 3 π r 2 h ⇒ d V d t = π 3 r 2 d h d t + h ⋅ 2 r d r d t = 0 ⇒ r d h d t = - 2 h d r d t Also, r h = t a n π 4 ⇒ r = h ∴ d h d t = - 2 d r d t ⇒ d r d t = - 1 2 d h d t ⇒ d r d t = + 1 ⇒ radius increases at 1 m / s .