NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice
The points on the curve y = x 2 which are closest to the point P 0,1 are
Options
- A± 2 , 2
- B± 1 2 , 1 4
- C± 1 2 , 1 2
- D± 1 4 , 1 16
Correct answer
C. ± 1 2 , 1 2
Step-by-step solution
Let, the general point on the curve be Q α , α 2 ∴   P Q 2 = α 2 + α 2 - 1 2 = D (say) ⇒ D = α 4 - α 2 + 1 ⇒ d D d α = 4 α 3 - 2 α For P Q to be minimum, α 2 = 1 2 ⇒ α = ± 1 2 ∴ Q is ± 1 2 , 1 2