NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice
The number of solutions of x 3 + 4 x - 1 = 0 in the interval x ∈ - 2,1 is
Correct answer
1
Step-by-step solution
Let, f x = x 3 + 4 x - 1 ∴ f ' x = 3 x 2 + 4 > 0 , ∀ x ∈ R Also, f - 2 = - 17 < 0 & f 1 = 4 > 0 As f x is continuous and increasing, it has exactly one root in the interval - 2,1 .