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AP EAMCET202420 May 2024Morning ShiftMathematicsHyperbolaActual

If a tangent to the hyperbola x^2- y^2 3 =1 is also a tangent to the parabola y^2=8 x . then equation of such tangent with the positive slope is

Options

  1. Ay-x- 1 2 =0
  2. By-2 x-1=0
  3. C2 y-4 x-1=0
  4. Dy-x-1=0

Correct answer

B. y-2 x-1=0

Step-by-step solution

Eq. of tangent to y^2=8 x is y=m x+ 2 m Eq. of tangent to x^2- y^2 3 =1 is y=m x m^2-3 On comparing we get m= 2 tangent with + ve slope is y-2 x-1=0

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