NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice
The number of real values of x that satisfies the equation x 4 + 4 x 3 + 12 x 2 + 7 x - 3 = 0 is
Correct answer
2
Step-by-step solution
Let, f x = x 4 + 4 x 3 + 12 x 2 + 7 x - 3 ∴ f ′ x = 4 x 3 + 12 x 2 + 24 x + 7 f ″ x = 12 x 2 + 2 x + 2 i.e. f '' x > 0 ,   ∀ x ∈ R Also, f 0 = - 3 Hence, f x = 0 has 2 real roots