NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice

In the interval 0,2 , on which of the following function Lagrange's mean value theorem is not applicable?

Options

Af x = sin ⁡ x x x ≠ 0 1 x = 0
Bf x = 1 - x x < 1 1 - x 2 x ≥ 1
Cf x = x 2 x
Df x = e x - 1

Correct answer

B. f x = 1 - x x < 1 1 - x 2 x ≥ 1

Step-by-step solution

Note that LMVT is applicable in a , b if f x is continuous in a , b and differentiable in a , b Since f x = 1 - x x < 1 1 - x 2 x ≥ 1 is non-differentiable at x = 1 , hence LMVT cannot be applied to it in 0,2

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