NTA Abhyas JEE Main2020MathematicsApplication of DerivativesPractice
For f : R → R ,   f x = x 4 - 8 x 3 + 22 x 2 - 24 x , the sum of all local extreme values of f x is equal to
Options
- A- 9
- B- 8
- C- 17
- D- 26
Correct answer
D. - 26
Step-by-step solution
f ′ x = 4 x 3 − 6 x 2 + 11 x − 6 = 4 x - 1 x - 2 x - 3 Hence, x = 1 , 2 , 3 are points of extrema So, f 1 + f 2 + f 3 - 9 + - 8 + - 9 = - 26