NTA Abhyas JEE Main2020MathematicsBinomial TheoremPractice
The first integral term in the expansion of 3 + 2 3 9 , is the
Options
- A2 n d t e r m
- B3 r d t e r m
- C4 t h t e r m
- D5 t h t e r m
Correct answer
C. 4 t h t e r m
Step-by-step solution
3 + 2 3 9 = 3 1 2 + 2 1 3 9 ∴     T r + 1 = 9 C r 3 1 2 9 - r 2 1 3 r For first integral term, r = 3 ⇒ T 3 + 1 =   9 C 3 3 3 . 2 1 i.e., T 3 + 1 = T 4