NTA Abhyas JEE Main2020MathematicsBinomial TheoremPractice
If 2 2020 + 2021 is divided by 9 , then the remainder obtained is
Options
- A0
- B1
- C3
- D7
Correct answer
C. 3
Step-by-step solution
2 2020 = 2.2 2019 = 2 . 2 3 673 = 2 9 - 1 673 = 2 9 673 - 673 C 1 ⋅ 9 672 + 673 C 2 ⋅ 9 671 + 673 C 672 9 - 1 = 2 (a multiple of 9 - 1 ) 2 2020 + 2021 = 9 K + 2019 9 K + 2019 when divided by 9 gives remainder 3