NTA Abhyas JEE Main2020MathematicsBinomial TheoremPractice
The coefficient of x 13 in the expansion of 1 - x 5 1 + x + x 2 + x 3 4 is
Options
- A24
- B12
- C6
- D4
Correct answer
D. 4
Step-by-step solution
Let, E = 1 - x 5 1 + x 1 + x 2 4 = 1 - x 1 - x 4 1 + x 4 1 + x 2 4 = 1 - x 1 - x 2 4 1 + x 2 4 = 1 - x 1 - x 4 4 = 1 - x 1 - 4 x 4 + 6 x 8 - 4 x 12 + x 16 Coefficient of x 13 is - 1 - 4 = 4