NTA Abhyas JEE Main2020MathematicsBinomial TheoremPractice

The coefficient of x 4 in the expansion of 1 + 5 x + 9 x 2 + 13 x 3 + 17 x 4 + . … … 1 + x 2 11 is equal to

Options

AC 2 11 + 4 C 1 11 + 3
BC 2 11 + 3 C 1 11 + 4
C3 C 2 11 + 4 C 1 11 + 3
D171

Correct answer

D. 171

Step-by-step solution

Coefficient of x 4 in 1 + 5 x + 9 x 2 + 13 x 3 + 17 x 4 + . … … . 1 + 11 x 2 + C 2 11 x 4 + . … … Coefficient of x 4 is = C 11 2 + 9 × 11 + 17 × 1 = 11 × 10 2 + 99 + 17 = 55 + 99 + 17 = 171

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